Two perfectly elastic balls of same mass m are moving with velocities `u_(1)` and `u_(2)`. They collide elastically n times. The kinetic energy of the system finally is:

Two particles of same mass m moving with velocities u_(1) and u_(2) collide perfectly inelastically. The loss of energy would be :

Two particles of same mass m moving with velocities u_(1) and u_(2) collide perfectly inelastically. The loss of energy would be :

Two particles of same mass 'm' moving with velocities vecv_1= vhati, and vecv_2 = (v/2)hati + (v/2)hatj collide in-elastically. Find the loss in kinetic energy

Two particles of same mass 'm' moving with velocities vecv_1= vhati, and vecv_2 = (v/2)hati + (v/2)hatj collide in-elastically. Find the loss in kinetic energy

Two particles of same mass 'm' moving with velocities vecv_1= vhati, and vecv_2 = (v/2)hati + (v/2)hatj collide in-elastically. Find the loss in kinetic energy

Two particles of mass m & 2m have velocities u hat( j) & u hat( i ) respectively . They collide completely inelastically. Find the loss in kinetic energy of the system.

Two particles of mass m & 2m have velocities u hat( j) & u hat( i ) respectively . They collide completely inelastically. Find the loss in kinetic energy of the system.

A ball of mass '2m' moving with velocity u hat(i) collides with another ball of mass 'm' moving with velocity - 2 u hat(i) . After the collision, mass 2m moves with velocity (u)/(2) ( hat(i) - hat(j)) . Then the change in kinetic energy of the system ( both balls ) is