The area bounded by the graph of `y=f(x), f(x) gt0` on [0,a] and x-axis is `(a^(2))/(2)+(a)/(2) sin a +(pi)/(2) cos a ` then find the value of `f((pi)/(2))`.

Let f (x) be a continous function such that the area bounded by the curve y =f (x) x-axis and the lines x=0 and x =a is (a ^(2))/( 2) + (a)/(2) sin a+ pi/2 cos a, then f ((pi)/(2)) is

If f'(x)=3x^(2)sin x-x cos x x!=0 f(0)=0 then the value of f((1)/(pi)) is

The function f(x) is a non - negative continous function .The area of the region bounded by the curve y=f(x) , X - axis , x=(pi)/(4), x= beta gt (pi)/(4) is beta sinbeta + (pi)/(4) cos beta + sqrt(2) beta then f ((pi)/(2)) ……

If f'(x)=3x^(2)sin x-x cos x ,x!=0 f(0)=0 then the value of f((1)/(pi)) is

If f(x) is a non - negative function such that the area bounded by y=f(x), x - axis and the lines x = 0 and x=alpha is 4alpha sin alpha+2 sq. Units ( AA alpha in [0, pi] ), then the value of f((pi)/(2)) is equal to

If f(x) is a non - negative function such that the area bounded by y=f(x), x - axis and the lines x = 0 and x=alpha is 4alpha sin alpha+2 sq. Units ( AA alpha in [0, pi] ), then the value of f((pi)/(2)) is equal to

Let f(x)>0 be a continuous function such that the area bounded by the curve y=f(x),x -axis and the lines x=0 and x=lambda is + (lambda^(2))/(2)+cos^(2)lambda .Then f((pi)/(4)) is

The area bounded by the curve y=|cos x-sin x|,0<=x<=(pi)/(2) and above x - axis is

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), x-axis and the ordinates x=pi/4 and x=beta gt pi/4 is : (beta sin beta + pi/4 cos beta +sqrt2beta) . Then f(pi/2) is :

Let f(x) be non- negative continuous function such that the area bounded by the curve y=f(x) , x- axis and the ordinates x= (pi)/(4) and x = beta ( beta gt (pi)/(4)) is beta sin beta + (pi)/(4) cos beta + sqrt(2) beta . Then the value of f((pi)/(2)) is-