A liquid cools from 70 °C to 60 °C in 5 minutes. If the temperature of the surrounding is constant at 30 °C, then the time taken by the liquid to cool from 60 °C to 50 °C is

A liquid cools from 70^(@) C to 60^(@) C in 5 minutes. If the temperautre of the surrounding is 30^(@) C, what is the time taken by the liquid to cool from 50^(@) C to 40^(@) C ?

A body cools from 80°C to 50°C in 5 minutes.If the temperature of the surrounding is 20°C ,Calculate the time it takes to cool from 60°C to 30°C .

A metal sphere cools from 72^(@)C to 60^(@)C in 10 minutes. If the surroundings temperature is 36^(@)C , then the time taken by it to cool from 60^(@)C to 52^(@)C is

A liquid contained in a beaker cools from 80^(@)C to 60^(@)C in 10 minutes. If the temperature of the surrounding is 30^(@)C , find the time it will take to cool further to 48^(@)C . Here cooling take place ac cording to Newton's law of cooling.

A body takes 5 minutes to cool from 90^(@)C to 60^(@)C . If the temperature of the surroundings is 20^(@)C , the time taken by it to cool from 60^(@)C to 30^(@)C will be.

A body cool from 90^@C to 70^@C in 10 minutes if temperature of surrounding is 20^@C find the time taken by body to cool from 60^@C to 30^@C . Assuming Newton’s law of cooling is valid.

A body cool from 90^@C to 70^@C in 10 minutes if temperature of surrounding is 20^@C . find the time taken by body to cool from 60^@C to 30^@C . Assuming Newton’s law of cooling is valid.

A body cools from 70^(@)C to 50^(@)C in 5 minutes. Temperature of surroundings is 20^(@)C . Its temperature after next 10 minutes is