If `int(x^2-1)/((x+1)^2sqrt(x(x^2+x+1)))\ dx=A\ tan^(- 1)((x^2+x+1)/x)+c` in which `c` is a constant then `A=`

If int((x^(2)-1))/((x+1)^(2)sqrt(x(x^(2)+x+1)))dx=ATan^(-1)(sqrt(x^(2+)x+1)/(x))+c in which c is a constant then A =

If int(1)/((x+1)sqrt(x-1))dx=k.tan^(-1)sqrt((x-1)/(2))+c then k =

If int(x-1)/((x+x sqrt(x)+sqrt(x))+sqrt(sqrt(x)(x+1)))dx=4tan^(-1)(g(x))+c where c is constant of integration, then g^(2)(1)=

int(1)/((1+x^(2))sqrt(tan^(-1)x))dx=?

int ((x^2 -1)dx)/((x^4 + 3x^2 + 1) tan^-1((x^2 + 1)/x)) = k logabs(tan^-1((x^2 +1)/x)) + c

If int(1)/((x^2+1)(x^2+4))dx=a tan^(-1). x+b tan^(-1).(x)/(2)+c , then :

int tan^(-1)((sqrt(1+x^(2))-1)/(x))dx

If int(dx)/((x+1)^(2)(x^(2)+2x+2))=(A)/(x+1)+B tan^(-1)(x+1)+C, where A and B are constants and C is the constant of integration, then |A-B| is equal to

If int(dx)/((x+1)^(2)(x^(2)+2x+2))=(A)/(x+1)+B tan^(-1)(x+1)+C, where A and B are constants and C is the constant of integration, then |A-B| is equal to

int (e^(x) (x^(2) tan^(-1) x + tan^(-1) x + 1))/( x^(2) + 1) dx is