If the standard deviation of n observation `x_(1), x_(2),…….,x_(n)` is 5 and for another set of n observation `y_(1), y_(2),………., y_(n)` is 4, then the standard deviation of n observation
`x_(1)-y_(1), x_(2)-y_(2),………….,x_(n)-y_(n)` is

The standard deviation of n observation x_(1),x_(2),……x_(n) is 6. The standard deviation of another set of n observations y_(1),y_(2),………..y_(n) is 8. What is the standard deviation of n observations x_(1)-y_(2),x_(2)-y_(2),………..,x_(n)-y_(n) ?

Mean deviation for n observation x_(1),x_(2),…..x_(n) from their mean bar x is given by

Mean deviation for n observation x_(1),x_(2),…..x_(n) from their mean bar x is given by

Mean deviation for n observations x_(1), x_(2),….., x_(n) from their mean bar(x) is given by :

If the standard deviation of x_(1),x_(2),….,x_(n) is 3.5 then the standard deviation of -2x_(1)-3, -2x_(2)-3,….,-2x_(n)-3 is

If the standard deviation of x_(1),x_(2),….,x_(n) is 3.5 then the standard deviation of -2x_(1)-3, -2x_(2)-3,….,-2x_(n)-3 is

The geometric mean of the observation x_(1),x_(2),x_(3),……..,_(n) is G_(1) , The geometric mean of the observation y_(1),y_(2),y_(3),…..y_(n) is G_(2) . The geometric mean of observations (x_(1))/(y_(1)),(x_(2))/(y_(2)),(x_(3))/(y_(3)),……(x_(n))/(y_(n)) us

A set of n values x_(1),x_(2),…….,x_(n) has standard deviation sigma . The standard deviation of n values x_(1)-k,x_(2)-k,…….,x_(n)-k is

If the standard deviation of x_(1),x_(2),...x_(n) is "3.5," then the standard deviation of -2x_(1)-3,-2x_(2)-3,......,-2x_(n)-3 is