Number of bonds in given compound is:
`CH_(2)=C=CH-C=CH`

Write down the number of sigma and pi - bonds in the given compound : CH_(3) CH = CH C -= CH

The decreasing order of bond dissociation energy of C-H bond in given compound is :- (A) CH_(3)-H (B) CH_(3)-CH_(2)-H CH_(2)=CH-CH_(2)-H (D)

The decreasing order of bond dissociation energy of C-H bond in given compound is :- (A) CH_(3)-H (B) CH_(3)-CH_(2)-H CH_(2)=CH-CH_(2)-H (D)

Total number of sp^2 hybridised atoms present in the given compound is CH_2= CH- C= C - CN

CH_(2)=C=CH-CH_(3), total number of sigma & pi bonds in given compound will be :-

Ch_(2)=C=Ch-CH_(3), total numbe rof sigma & pi bonds in given compound will be :-

Find the number of geometrical isomers of the given compound . C_(6)H_(5) - CH = CH - CH-CH = CH - CH = CH - COOH

The ratio of the number of sp, sp^(2) , and sp^(3) orbitals in the compound is CH_(3)-CH=C=CH-C-=C-CH_(3)