A nucleus of mass number A has mass defect `(Deltam)` what is BE per nucleon of this nucleus?

A nucleus of mass number A, has a mass defect Deltam . Give the formula, for the binding energy per nucleon of this nucleus.

The binding energy per nucleon are 53 Mev, 6.2 MeV and 7.4 MeV for the nucleus with mass number ,3,4 and 5 respectively . If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei of mass number 4, then

The binding energy per nucleon are 5.3 Mev, 6.2 MeV and 7.4 MeV for the nucleus with mass number ,3,4 and 5 respectively . If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei of mass number 4, then

A nuclear of mass M +deltam is at rest and decay into two daughter nuclei of equal mass (M)/(2) each speed is c The binding energy per nucleon for the nucleus is E_(1) and that for the daugther nuclei is E_(2) Then

A nuclear of mass M +deltam is at rest and decay into two daughter nuclei of equal mass (M)/(2) each speed is c The binding energy per nucleon for the nucleus is E_(1) and that for the daugther nuclei is E_(2) Then

A nuclear of mass M +deltam is at rest and decay into two daughter nuclei of equal mass (M)/(2) each speed is c The binding energy per nucleon for the nucleus is E_(1) and that for the daugther nuclei is E_(2) Then