A wire frame ABCD has a soap film. The wire BC can slide on the frame without friction and it is in equilibrium in the position shown in the figure. Find m, if T is the surface tension of the liquid.

A square wire frame of length l is dipped in a solution. When the frame is taken out, a liquid film is formed. What is the algebraic sum of all the force acting on the frame due to surface tension of the liquid? (given sigma= surface tension of the liquid).

A wire is bent an an angle theta . A rod of mass m can slide along the bended wire without friction as shown in Fig. A soap film is maintained in the frame kept in a vertical position and the rod is in equilibrium as shown in the figure. If rod is displaced slightly in vertical direction, then the time period of small oscillation of the rod is

A wire is bent an an angle theta . A rod of mass m can slide along the bended wire without friction as shown in Fig. A soap film is maintained in the frame kept in a vertical position and the rod is in equilibrium as shown in the figure. If rod is displaced slightly in vertical direction, then the time period of small oscillation of the rod is

A wire is bent an an angle theta . A rod of mass m can slide along the bended wire without friction as shown in Fig. A soap film is maintained in the frame kept in a vertical position and the rod is in equilibrium as shown in the figure. If rod is displaced slightly in vertical direction, then the time period of small oscillation of the rod is

A soap film is formed on a rectangular frame of length 7 cm dipping in soap solution. The frame hanges from the arm of a balance. An extra weight of 0.38 g is to be placed in the opposite pan to balance the pull on the frame. Calculate the surface tension of the soap solution. "Given" g= 980 "cms"^(-2).

A liquid film is formed over a frame ABCD as shown in figure. Wire CD can slide without friction. The mass to be hung from CD to keep it in equilibrium is

U - shaped film of a liquid is formed between a wire frame and movable wire 5 cm long. Then the force required to hold the wire in equilibrium is , (Surface tension of liquid is 0.024 N/m )

A thin and light thread of sufficient length L is attached to a wire frame. The frame (along with the thread) is dipped into soap solution. When the frame is taken out of the solution, the thread takes the form of a semicircle with a soap film extending between the frame and the thread as shown in the figure ( a ). Now the thread is deformed into two semicircles by applying a force of F at the middle of the thread, as a result the film gets strectched as shown in the figure. ( b ). Calculate the surface tension of the soap solution.