In a `Delta ABC` `a/b=2+sqrt(2) " and " angle C = 60 ^@` Then the ordered pair `(angle A , angle B)` is equal to :

In a Delta ABC a/b=2+sqrt(3) " and " angle C = 60 ^@ Then the ordered pair (angle A , angle B) is equal to :

In Delta ABC , a/b = 2 + sqrt2 " and " angle C = 60^(@) . Then the ordered pair (angle A , angle B) is equal to

In a Delta ABC b= sqrt(3)+1, c=sqrt(3)-1 , angle A = 60 ^@ then the value of tan (B-C)/(2) is :-

In a Delta ABC b= sqrt(3)+1, c=sqrt(3)-1 , angle A = 60 ^@ then the value of tan (B-C)/(2) is :-

In a triangle ABC,a/b=2+sqrt(3) and /_C=60^(@) then angle A and B is

In a triangle ABC,a/b=2+sqrt(3) and /_C=60^(@) then angle A and B is

In a Delta ABC angle A + angle B = 145^(@), 2 angle B + angle C = 180^(@) Find angle A and angle B

In Delta ABC , b = sqrt 3+ 1 , c sqrt3-1 and angle A = 60 ^(@) then the value of tan (( B-C)/( 2)) =

With the usual notation , in Delta ABC if angle A+ angle B= 120^@ ,a=sqrt(3)+1 " and " b= sqrt(3)-1 then the ratio angle A : angle B is :