1 mol of a non-ideal gas undergoes the given change: (2 atm, 3L, 95 K)`to`(4 atm, 5L, 245 K). In this process, if increase in internal energy of the gas is 30 L`*`atm, then what will be its change in enthalpy?

One mole of a non-ideal gas undergoes a change of state ( 2.0 atm, 3.0L, 95 K) rarr (4.0 atm, 5.0L, 245 K) with a change in internal energy , Delta U= 30.0 L. atm . Calculate change in enthalpy of the process in L. atm .

One mole of a non-ideal gas undergoes a change of state ( 2.0 atm, 3.0L, 95 K) rarr (4.0 atm, 5.0L, 245 K) with a change in internal energy , Delta U= 30.0 L. atm . Calculate change in enthalpy of the process in L. atm .

One mole of non-ideal gas undergoes a change of state ( 2.0 "atm" , 3.0 L , 95 K ) to ( 4.0 "atm" , 5.0 L , 245 K ) with a change in internal energy, DeltaU=30.0 L atm . The change in enthalpy (DeltaH) of the process in L "atm" is

One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 90K) rarr (4.0 atm, 5.0 L, 245 K) with a change in internal energy, Delta U = 30.0 L atm . The change in enthalpy (Delta H) of the process in L atm is (Give your answer after dividing with 11)

One mole of non - ideal gas undergoes a change of state (2.0 atm , 3 .0 L , 95 K rarr (4.0 atm , 5.0 L , 245 K) with a change in internal energy , DeltaU = 30.0L atm . The change in enthalpy (DeltaH) of the process in L atm is

One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.01, 95K) to (4.0 atm, 5.01, 245K) with a change in internal energy, DeltaU=30.0L atm. The change in enthalpy DeltaH of the process in L atm is.