Solve `sin x tan x -sin x+ tan x-1=0` for `x in [0, 2pi]`.

The number of solutions of the equation sin x tan x - sin x + tna x - 1 = 0 for x in [0, 2 pi] is

Solve sin x + (tan x) / (2) = 0

Given that the sum of the solution of sin x tan x-sin x+tan x-1=0 over [0,2 pi] is k pi, then value of k is

Solve the equation sin x tan x - 1 = tan x - sin x .

Solve tan x+tan 2x+tan 3x = tan x tan 2x tan 3x, x in [0, pi] .

Solve tan x+tan 2x+tan 3x = tan x tan 2x tan 3x, x in [0, pi] .

Solve the equation sin x tan x-1=tan x-sin x

If sin^(2) x tan x + cos ^(2) x cot x - sin 2 x = 1 + tan x + cot x x in (0, pi) then x =

Draw the graph of cosx, sin x and tan x in [0, 2pi]