A body of mass `m_1=4` kg moves at `5 hati m//s` and another body of mass `m_2=2` kg moves at `10 hati m//s`. The kinetic energy of center of mass is

A body of mass m_(1) = 4kg moves at 5 hat(i) ms^(-1) and another body of mass m_(2) = 2kg moves at 10hat(i)ms^(-1) . The kinetic energy of center of mass is

A body of mass m_(1) = 4kg moves at 5 hat(i) ms^(-1) and another body of mass m_(2) = 2kg moves at 10hat(i)ms^(-1) . The kinetic energy of center of mass is

A body of mass 2 kg moves with a velocity of 5 m/s. Find its kinetic energy.

A body of mass 0.5 kg moving with a velocity of 6 m//s collides with another body of mass 2 kg moving at 2 m//s and travelling in opposite direction. If the two bodies travel together after the collision, find the velocity of combined mass and the loss of kinetic energy.

A body of mass 5 kg moving with a velocity 10 m/s collides with another body of the mass 20 kg at, rest and comes to rest. The velocity of the second body due to collision is

A body of mass 1 kg moving with velocity 5 m/s collides with another body of mass 2 kg moving with velocity 1.5 m/s in opposite direction. If the coefficient of restitution is 0.8, their velocities aftter collision respectively are

A body of mass 1 kg moving with velocity 5 m/s collides with another body of mass 2 kg moving with velocity 1.5 m/s in opposite direction. If the coefficient of restitution is 0.8, their velocities aftter collision respectively are

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is