If the displacement of a particle is given by `y(t)=A sin (omega t +phi)`, then find the maximum velocity of the particle.

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

The displacement of a particle executing SHM is given by y=0.25 sin(200t) cm . The maximum speed of the particle is

The displacement of a particle is given by x(t) = (4t ^(2) +8) meter. The instantaneous velocity of a particle at t = 2s is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200t cm. The maximum speed of the particle is

The displacement of a particle executing SHM is given by y=0.5 sin100t cm . The maximum speed of the particle is