P and Q are two point on the line `x-y+1=0`, if O is the origin and ` bar (OP)= bar (OQ)=5` unit, find the area of `Delta OPQ`.

P and Q are two points on the line x-y+1=0 , If OP=OQ=6 then length of median through O is

P and Q are two points on the line x-y+1=0. If OP=OQ=6 then length of median through O is

If P and Q are two points on the line 3x + 4y = - 15, such that OP = OQ = 9 units, the area of the triangle POQ will be

If O is the origin and P = (1, -2, 1) and OP bot OQ , then Q =

If P,Q are two point on the line 3x+4y+15=0 such that OP=OQ=9, then the area of Delta OPQ is

ABC is an equilateral triangle. P and Q are two points on bar(AB) and bar(AC) respectively such that bar(PQ) || bar(BC) . If bar(PQ) = 5cm , then area of Delta APQ is :

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is