The length of normal to the curve `x=a(theta+sin theta), y=a(1-cos theta),` at `theta=(pi)/(2)` is

Find the length of normal to the curve x=a(theta+sin theta),y=a(1-cos theta) at theta=(pi)/(2)

The slope of the normal to the curve x=a(theta-sin theta),y=a(1-cos theta) at theta=(pi)/(2)

The slope of the nomal to the curve x = a(theta - sin theta), y = a(1-cos theta) at theta = pi/2 is

Find the equations of tangent and normal to the curve x=a( theta- sin theta), y=a(1 -cos theta)" at "theta=pi//2

The equation of tangent to the curve x=a(theta+ sin theta), y=a (1+ cos theta)" at "theta=(pi)/(2) is

Find the slope of the normal to the curve x=1 -a sin theta , y = b cos^(2) theta at theta= (pi)/(2) .