((1 + "cos"(pi)/(8) -i "sin"(pi)/(8))/(1...

`((1 + "cos"(pi)/(8) -i "sin"(pi)/(8))/(1 + "cos"(pi)/(8) + i "sin" (pi)/(8)))^(12)=`

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((1+cos""(pi)/(8)-isin""(pi)/(8))/(1+cos""(pi)/(8)+isin""(pi)/(8)))^(8)

((1+"cos"(pi)/(8)+"isin"(pi)/(8))/(1+"cos"(pi)/(8)-"isin"(pi)/(8)))^(8)=

[(1 + cos ((pi) / (8)) + i sin ((pi) / (8))) / (1 + cos ((pi) / (8)) - sin ((pi) / (8 )))] ^ (8) =?

(1 + cos"" (pi)/(8))(1 + cos"" (3pi)/(8)) (1 + cos"" (5pi)/(8))(1 + cos"" (7pi)/(8)) =

Evaluate : cos ""(pi)/(8) sin ""(pi)/(8)

Prove that (1+"cos"(pi)/(8))(1+"cos"(3pi)/(8))(1+"cos"(5pi)/(8))(1+"cos"(7pi)/(8))=(1)/(8) .

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