The point of intersection of the line `(x-1)/3=(y+2)/4=(z-3)/-2` and the plane `2x-y+3z-1=0`, is

The distance of the point (2,3,-4) from the point of intersection of the line (x-1)/-3 = (y-2)/2 = (z-2)/1 and the plane 2x-3y-z-20 =0 is

Point of intersection of the line (x-1)/2 = (y-2)/3 = (z+3)/4 and the plane 2x+4y -z=1 is

Distance of the origin from the point of intersection of the line (x)/(2)=(y-2)/(3)=(z-3)/(4) and the plane 2x+y-z=2 is

The point of intersection of the line ( x-1)/( 3) = (y+2)/( 4) = (z-3)/(-2) and plane 2x - y + 3z -1=0 is

Find the points of intersection of the line (x-2)/(-3)=(y-1)/2=(z-3)/2 and the plane 2x+y-z=3 .

Find the points of intersection of the line (x-2)/(-3)=(y-1)/2=(z-3)/2 and the plane 2x+y-z=3 .

The point of intersection of the line (x)/(1)=(y-1)/(2)=(z+2)/(3) and the plane 2x+3y+z=0 is