The equivalent conductance of an infinitely dilute solution of `NH_4CI` is `150` and the ionic conductance of `OH^(-)` and `CI^(-)` ions are `198` and ` 76` respectively. If the equivalent conductance of a ` 0.01 N` solution of ` NH_4 OH` is `9.6` Wat will be its degree of dissociation ?

The equivalent conductances of an infinitely dilute solution NH_(4)CI is 150 and the ionic conductances of OH^(-) and CI^(-) ions are 198 and 76 respectively. What will be the equivalent conductance of the solution of NH_(4)OH at infinite dilution. if the equivalent conductance of a 0.01N solution NH_(4)OH is 9.6, what will be its degree of dissociation.

The equivalent conductances of an infinitely dilute solution NH_(4)CI is 150 and the ionic conductances of OH^(-) and CI^(-) ions are 198 and 76 respectively. What will be the equivalent conductance of the solution of NH_(4)OH at infinite dilution. if the equivalent conductance of a 0.01N solution NH_(4)OH is 9.6, what will be its degree of dissociation.

The equivalent conductances of an infinitely dilute solution NH_(4)CI is 150 and the ionic conductances of OH^(-) and CI^(-) ions are 198 and 76 respectively. What will be the equivalent conductance of the solution of NH_(4)OH at infinite dilution. if the equivalent conductance of a 0.01N solution NH_(4)OH is 9.6, what will be its degree of dissociation.

The equivalent conductance of an infinitely dilute solution of NH_(4)Cl is 150 and te ionic conductance of OH^(-) ad Cl^(-) ions are 198 and 76 respectively. What will be the equivalent conductance of the solution of NH_(4)OH at infinite dilution. if the equivalent conductance of a 0.01 N solution NH_(4)OH is 9.6, what will be its degree of dissociation?

Calculating The Degree of ionization: The molar conductance of an infinitely dilute solution NH_(4)Cl is 150 S cm^(2) mol^(-1) and the limiting ionic conductacnes of Cl^(-) and OH^(-) ions are 76 and 198 S cm^(2) mol^(-1) respectively. If the molar conductivity of a 0.01 M solution of NH_(4)OH is 9.6 S cm^(2) mol^(-1) , what will be its degree of ionization Strategy: At any concentration C , if alpha is the degree of ionization then it can be approximented to the ratio of molar conductivity Lambda_(m)^(c) at the concentration C to limiting molar conducting, Lambda_(m)^(0) . We are given Lambda_(m)^(c) but we need to find Lambda_(m)^(0) .

The equivalent conductance of an infinitely dilute solution of Al_(2)(SO_(4))_(3) is Lambda^(@) . What is the value of Lambda_(m)^(@) for the solution?

Equivalent conductance at infinite dilution of NH_4CI , NaOH and NaCl are 129.8, 217.4 and 108.45 mho cm^2 gm equivalent-' respectively.Calculate the equivalent conductance of HN_4OH at infinite dilution.