If in a triangle ABC, `(cosA)/a=(cosB)/b=(cosC)/c`,then the triangle is

Fill int the blanks choosing correct answer from the bracket. In triangle ABC if cosA/a = cosB/b = cosC/c then the triangle is _____.

In a triangle ABC, (cosB+cosC)/(1-cosA) =

In a triangle ABC, if (cosA)/a=(cosB)/b=(cosC)/c and the side a =2 , then area of triangle is

In a triangle ABC, if (cosA)/a=(cosB)/b=(cosC)/c and the side a =2 , then area of triangle is

In triangleABC , If cosA+cosB+cosC=(3)/(2) , then the triangle is

If in a Delta A B C ,(cosA)/a=(cosB)/b=(cosC)/c , then find the measures of angles A ,\ B ,\ Cdot

In any triangle ABC : If (cosA)/a= (cosB)/b , prove that the triangle is isosceles.

In triangle ABC, 2(bc cosA-ac cosB-ab cosC)=

If in triangle ABC cosA+cosB+cosC=3/2 then prove that triangle is equilateral