If the planes `3x-2y+2z+17=0 and 4x+3y-kz=25` are mutually perpendicular , then k=

The value of k for which the planes 3x-6y-2z=7 and 2x+y-kz=5 are perpendicular to each other is

Find the value of 'k' for which the plane : 3x - 6y - 2z = 7 and 2x + y - kz = 3 are perpendicular to each other.

Find the value of k for whicj the planes: 3x-6y-2z=7 and 2x+y-kz=5 are perpendicular to each other.

The value of k for which the planes 3x-6y-2z=7 and 2x+y-kz=5 areperpendicular to each other is

Plane passing through the intersection of the planes x + 2y + z- 1 = 0 and 2x + y + 3z - 2 = 0 and perpendicular to the plane x + y + z - 1 = 0 and x + ky + 3z - 1 = 0. Then the value of k is

Plane passing through the intersection of the planes x + 2y + z - 1 = 0 and 2x + y + 3z - 2 = 0 and perpendicular to the plane x + y + z - 1 = 0 and x + ky + 3z - 1 = 0. Then the value of k is

If the planes 2x + 3y - z + 5 = 0, x + 2y – kz + 7 = 0 are perpendicular then k=

Find the equation of the plane through the intersection of the planes 2x - 3y + z - = 0 and x - y + z + 1 = 0 and perpendicular to the plane x + 2y - 3z + 6 = 0.

Find the equation of the plane through the line of intersection of the planes: x+3y-z+1=0 and x+y-2z+3=0 and perpendicular to the plane 3x-y-2z-4=0