Home
Class 12
CHEMISTRY
K(sp) of AgCl is 1.96xx10^(-10). 100 mL ...

`K_(sp)` of AgCl is `1.96xx10^(-10)`. 100 mL of saturated AgCl solution is titrated with `1xx10^(-5) M NH_(4)SCN`. Volume of `1xx10^(-5) M NH_(4)SCN` required to precipitate all `Ag^(+)` from saturated AgCl solution as AgSCN is :

Promotional Banner

Similar Questions

Explore conceptually related problems

The solubility of Agcl (K_sp=1.2xx10^(-10)) in a 0.10 M NaCl solution is :

K_(sp) of AgCl is 1xx10^(-10) . Its solubility in 0.1 M KNO_(3) will be :

K_(sp) of AgCl is 1xx10^(-10) . Its solubility in 0.1 M KNO_(3) will be :

K_(sp) of AgCl is 1xx10^(-10) . Its solubility in 0.1 M KNO_(3) will be :

K_(sp) of AgCl in water at 25^(@)C is 1.8xx10^(-10) . If 10^(-5) mole of Ag^(+) ions are added to this solution. K_(sp) will be:

K_(sp) of AgCl in water at 25^(@)C is 1.8xx10^(-10) . If 10^(-5) mole of Ag^(+) ions are added to this solution. K_(sp) will be: