A circle is drawn on the chord of a circle `x^(2) + y^(2) =a^(2)` as diameter. The chord lies on the line `x+y = a`. What is the equation of the circle ?

A circle of radius 4 drawn on a chord of the parabola y^(2)=8x as diameter touches the axis of the parabola. Then the slope of the chord is

A circle of radius 4 drawn on a chord of the parabola y^(2)=8x as diameter touches the axis of the parabola. Then the slope of the chord is

The circle on the chord xcos alpha + ysin alpha =p of the circle x^2+y^2=r^2 as diameter is

if y=mx is a chord of a circle of radius a and the diameter of the circle lies along x -axis and one end of this chord in origin.The equation of the circle described on this chord as diameter is

Radius of circle which is drawn on a normal chord of y^(2)=4x as diameter and it pass through vertex is

The equation of the circle described on the chord 3x+y+5=0 of the circle x^(2) +y^(2) =16 as diameter is

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with center (2,1) ,then the radius of the circle is

If one of the diameters of the circle x^2+ y^2-2x-6y + 6=0 is a chord to the circle with centre (2, 1), then the radius of the circles is :