The radius of the circle `ax^2 + (2a-3) y^2 - 4x - 7 = 0` is : (A) 1 (B) `5/3` (C) `4/3` (D) 3

Find'the centre and radius of the circle (i) x^(2) +y^(2) + 4x - 1 = 0 (ii) 2 x^(2) + 2y^(2) = 3x - 5y + 7

The radical centre of three circles : x^2 + y^2 + x + 2y + 3 = 0, x^2 + y^2 + 2x + 4y + 5 = 0 and x^2 + y^2 - 7x - 8y - 9 = 0 is : (A) (- 2/3, - 2/3) (B) (1/3, 1/3) (C) (1/4, 1/4) (D) (0, 0)

The equation of the circle is 3x^(2) + 3y^(2)+6x-4y -1=0 . Then its radius is

Find the centre and radius of the circle 3x^(2)+ 3y^(2) - 6x + 4y - 4 = 0

Find the centre and radius of the circle 3x^(2)+ 3y^(2) - 6x + 4y - 4 = 0

The minimum radius of the circle which is orthogonal with both the circles x^2+y^2-12 x+35=0 and x^2+y^2+4x+3=0 is (a) 4 (b) 3 (c) sqrt(15) (d) 1

The minimum radius of the circle which is orthogonal with both the circles x^2+y^2-12 x+35=0 and x^2+y^2+4x+3=0 is (a) 4 (b) 3 (c) sqrt(15) (d) 1

The minimum radius of the circle which is orthogonal with both the circles x^2+y^2-12 x+35=0 and x^2+y^2+4x+3=0 is (a) 4 (b) 3 (c) sqrt(15) (d) 1

The coordinates of the centre of the circle 2x^(2)+2y^(2) + ax + by + c= 0 are (3, - 4), find a and b.