In the figure, AC=8cm, /ABC=90^(@). /BAC...

In the figure, `AC=8cm`, `/_ABC=90^(@)`. `/_BAC=60^(@)`, `/_ACB=30^(@)`. Complete the following activity to find `AB` and `BC`.

In `DeltaABC`,
By `30^(@)-60^(@)-90^(@)` triangle theorem,
`:.AB=(1)/(2)xxAC` and `BC=-AC`
`:.AB=(1)/(2)xx8` and `BC=-xx8`
`:.AB=square cm` and `BC= square cm`

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