Let `a, b in R` where `ab!=0` , then the graph of the straight line `ax-y+b=0` and the conic section `bx^2 +ay^2=ba` can be

If a^2+b^2-c^2-2ab = 0 , then the family of straight lines ax + by + c = 0

If a^2+b^2-c^2-2ab = 0 , then the family of straight lines ax + by + c = 0 is concurrent at the points

If a>0 and b^(2)-4ac<0, then the graph of y=ax^(2)+bx+c

Prove that the straight lines ax+by+c=0,bx+cy+a=0and cx+ay+b=0 are concurrent if a+b+c=0.When a!=b!=c .

C is the center of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 The tangent at any point P on this hyperbola meet the straight lines bx-ay=0 and bx+ay=0 at points Q and R, respectively. Then prove that CQ.CR=a^(2)+b^(2).

If the lines ax+by+c=0, bx+cy+a=0 and Cx+ay+b=0 are concurrent (a+b+cne0) then

Let a, b and c be real numbers such that 4a + 2b + c = 0 and ab gt 0. Then the equation ax^(2) + bx + c = 0 has

Let a, b and c be real numbers such that 4a + 2b + c = 0 and ab gt 0. Then the equation ax^(2) + bx + c = 0 has

Let a, b and c be real numbers such that 4a + 2b + c = 0 and ab gt 0. Then the equation ax^(2) + bx + c = 0 has