`2a^3+16b^3-5a-10b`

Let's find the L.C.M of the following algebraic expressions. 3a^2 - 5ab - 12b^2, a^5 - 27a^2 b^3, 9a^2 + 24ab + 16b^2

Factorize :27a^(3)+(1)/(64b^(3))+(27a^(2))/(4b)+(9a)/(16b^(2))

If (10a^3 + 4b^3) : (11a^3 - 15b^3 =7:5, then (3a + 5b) : (9a - 2b)=? यदि (10a^3 + 4b^3) : (11a^3 - 15b^3 =7:5 है, तो (3a + 5b) : (9a - 2b)=?

If (log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6) in terms of a and b is equal to (a) (2a+3b-1)/(5a+b-2) (b) (5a+b-1)/(3a+2b-2) (c) (3a+b-2)/(2a+3b-1) (d) (2a+5b-2)/(3a+b-1)

If (log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6) in terms of a and b is equal to (a) (2a+3b-1)/(5a+b-2) (b) (5a+b-1)/(3a+2b-2) (c) (3a+b-2)/(2a+3b-1) (d) (2a+5b-2)/(3a+b-1)

If (log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6) in terms of a and b is equal to (a) (2a+3b-1)/(5a+b-2) (b) (5a+b-1)/(3a+2b-2) (c) (3a+b-2)/(2a+3b-1) (d) (2a+5b-2)/(3a+b-1)

Simplify that: (4a b^2\ (-5a b^3))/(10 a^2b^2)

If a ,\ b ,\ c are positive real numbers, then root(5)(3125\ a^(10)b^5c^(10)) is equal to (a)\ 5a^2b c^2 (b) 25 a b^2c (c) 5a^3b c^3 (d) 125\ a^2b c^2