At two positons kinetic energy and potential energy of a particle are `K_(1) =10J: U_(1) =-20J, K_(2) = 20 J, U_(2)=-10 J`. In moving from 1 to 2 .

A body is displaced from position A to position B. Kinetic and potential energies of the body at positions A and B are K_(A)=50J, U_(A)=-30J, K_(B)=-10J and U_(B)=20J . Find work done by (a) conservative forces (b) all forces (c)forces other than covservative forces.

A body is displaced from position A to position B. Kinetic and potential energies of the body at positions A and B are K_(A)=50J, U_(A)=-30J, K_(B)=-10J and U_(B)=20J . Find work done by (a) conservative forces (b) all forces (c)forces other than covservative forces.

The potential energy of 1 kg particle is [U(x) = (0.25 x^4 - 0.5 x^2) J] If total mechanical energy is 2 J, then maximum K.E. is

The potential energy of 1 kg particle is [U(x) = (0.25 x^4) - (0.5 x^2) ] J If total mechanical energy is 2 J, then maximum KE is

The potential energy of 1 kg particle is [U(x) = (0.25 x^4) - (0.5 x^2) ] J If total mechanical energy is 2 J, then maximum KE is

In position A kinetic energy of a particle is 60 J and potential energy is -20 J. In position B, kinetic energy is 100 J and potential energy is 40 J. Then, in moving the particle from A to B

In position A kinetic energy of a particle is 60 J and potential energy is -20 J. In position B, kinetic energy is 100 J and potential energy is 40 J. Then, in moving the particle from A to B

At what displacement the kinetic is equal to the potential energy ? Hint : U = (1)/(2) kx^(2) , K = (1)/(2) (A^(2) - x^(2)) U = K

The kinetic energy in J of 1 mole of N_2 at 27^@ C is (R= 8.314 mol^(-1) k^(-1))