A ray emanating from the point (5,0) and is incident on the hyperbola `9x^2-16y^2=144` at the point P with abscissa 8. Then the equation of reflected ray after first refection, where the point P lies in first quadrant

A ray emanating from the point (5, 0) is meident on the hyperbola 9x^2-16 y^2=144 at the point P with abscissa 8. Find the equation of the reflected ray after the first reflection if point P lies in the first quadrant.

A ray emerging from the point (5, 0) is incident on the hyperbola 9x^2-16 y^2=144 at the point P with abscissa 8. Find the equation of the reflected ray after the first reflection if point P lies in the first quadrant.

A ray emerging from the point (5, 0) is incident on the hyperbola 9x^2-16 y^2=144 at the point P with abscissa 8. Find the equation of the reflected ray after the first reflection if point P lies in the first quadrant.

A ray emerging from the point (5, 0) is incident on the hyperbola 9x^2-16 y^2=144 at the point P with abscissa 8. Find the equation of the reflected ray after the first reflection if point P lies in the first quadrant.

A ray emanating from the point (5, 0) is INCIDENT on the hyperbola 9x^2-16 y^2=144 at the point P with abscissa 8. Find the equation of the reflected ray after the first reflection if point P lies in the first quadrant.

A ray emanating from the point (5,0) is INCIDENT on the hyperbola 9x^(2)-16y^(2)=144 at the point P with abscissa 8.Find the equation of the reflected ray after the first reflection if point P lies in the first quadrant.

A ray emanating from the point (dqrt(41), 0) is incident on the hyperbola 16x^(2)-25y^(2)=400 at the point P with abscissa10.Find the equation of a reflected ray after first reflection and point P lies in 2nd quadrant is

A ray emanating from the point (sqrt(41), 0) is incident on the hyperbola 16x^(2)-25y^(2)=400 at the point P with abscissa10.Find the equation of a reflected ray after first reflection and point P lies in 2nd quadrant is

A ray emanating from the point (sqrt(41), 0) is incident on the hyperbola 16x^(2)-25y^(2)=400 at the point P with abscissa10.Find the equation of a reflected ray after first reflection and point P lies in 2nd quadrant is

A ray emanating from the point (0, sqrt5 ) is incident on the ellipse 9x^(2)+4y^(2)=36 at the point P with abscissa 2. find the equation of the reflected ray after first reflection.