निऑन-23 निम्नलिखित प्रक्रिया से क्षयित होता है -
`""_(10)Ne^(23) to ""_(11)Na^(23)+ ""_(-1)beta^(0)+bar v`
`beta` कण द्वारा प्राप्त अधिकतम ऊर्जा ज्ञात करो-
`Ne^(23)` का परमाण्विक द्रव्यमान `=22.9945u`
`Na^(23)` का परमाण्विक द्रव्यमान `=22.9898u`.

Neon -23 decays in the following way ""_(10)^(23)Nerarr""_(11)^(23)Ne+""_(-1)e^0+barv. Find the minimum and maximum kinetic energy that the beta particle (""_(-1)e^(0)) can have . The atomic masses of ""^(23)Ne and ""^(23)Na are 22.9945 u and 22.9898 u, respectively.

In beta decay, ""_(10)Ne^(23) is converted into ""_(11)Na^(23) . Calculate the maximum kinetic energy of the electrons emitted, given atomic masses of ""_(10)Ne^(23) and ""_(11)Na^(23) arc 22.994466 u and 22.989770 u, respectively.

Complete the decay reaction ._10Ne^(23) to?+._-1e^0+? Also, find the maximum KE of electrons emitted during this decay. Given mass of ._10Ne^(23)=22.994465 u . mass of ._11Na^(23)=22.989768u .

Complete the decay reaction ._10Na^(23) to?+._-1e^0+? Also, find the maximum KE of electrons emitted during this decay. Given mass of ._10Na^(23)=22.994465 u . mass of ._11Na^(23)=22.989768u .

Find the Q-value of the given beta^(+) decay. ""_(11)N^(22) rarr ""_(10)Ne^(22) + ""_(+1) e^(0) Given that : Atomic mass of ""_(11)N^(22) is 21.994435 u, Atomic mass of ""_(11) Ne^(22) is 21.991384 u, Mass of ""_(+1)e^(0) is 0.0005486

The nucleus ""_(10)^(23)Ne decays by beta^(-) – mission. Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that: m (""_(10)^(23)Ne ) = 22.994466 u m (""_(11)^(23)Na ) = 22.989770 u.

The nucleus ""_(10)^(23)Ne decays by beta^(-) – mission. Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that: m (""_(10)^(23)Ne ) = 22.994466 u m (""_(11)^(23)Na ) = 22.989770 u.