A boy standing on a weighing machine notices his wight as 400 N. When he suddenly jumps upward the weight shown by the machine becomes 600 N. The acceleration with which the boy jumps up is : (Take `g=10m//s^(2)`)

A boy standing on a weighing machine observes his weight as 200 N. When he suddenly jumpes upwards, his friend notices that the reading increased to 400 N. The acceleration by which the boy jumped will be-

A boy standing on a weighing machine observes his weight as 200 N. When he suddenly jumpes upwards, his friend notices that the reading increased to 400 N. The acceleration by which the boy jumped will be-

A man is standing on a weighing machine with a block in his hand. The machine records w. When he takes the block upwards with some acceleration the machine records w_(1). When he takes the block down with some acceleration, the machine records w_(2). Then choose correct option

A man is standing on a weighing machine with a block in his hand. The machine records w. When he takes the block upwards with some acceleration the machine records w_(1). When he takes the block down with some acceleration, the machine records w_(2). Then choose correct option

A man is standing on a weighing machine with a block in his hand. The machine records w. When he takes the block upwards with some acceleration the machine records w_(1). When he takes the block down with some acceleration, the machine records w_(2). Then choose correct option

A man is standing in a lift which goes up and comes down with the same constant acceleration. If the ratio of the apparent weights in the two cases is 2 : 1 , then the acceleration of the lift is : (Take g = 10 m//s^(2) )

A boy of mass 50kg is standing on a weihing machine placed on the floor of a lift. The machine reads his weight in newtons. The reading of the machine if the lift is moving upwards with uniform speed of 10ms^(-1) .

A spring toy weighing 1 kg on a spring balance suddenly jumps upward. A boy standing near the toy notices that the scale of the balance reads 1.05 kg. In this process the maximum acceleration of the toy is - (g = 10 m sec^(–2))

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) , v = 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a= 2 m//s^(2), v = - 2 m//s