A small marble is projected with a velocity of `10 m//s` in a direction `45^(@)`from the y-direction on the smooth inclined plane. Calculate the magnitude `v` of its velocity of after `2 s` (Take `g = 10 m//s^(2))`

A small sphere is projected with velocity 5(m)/(s) in a direction 37^(@) from the horizontal y-axis on a smoother inclined plane. The motion of sphere takes plane in x-y plane. Magnitude of its velocity after 2 s is:

A small sphere is projected with velocity 5(m)/(s) in a direction 37^(@) from the horizontal y-axis on a smoother inclined plane. The motion of sphere takes plane in x-y plane. Magnitude of its velocity after 2 s is:

A small sphere is projected with a velocity of 3 ms^-1 in a direction 60^@ from the horizontal y - axis, on the smooth inclined plane (Fig. 5.197). The motion of sphere takes place in the x - y plane. Calculate the magnitude v of its velocity after 2 s . .

A small sphere is projected with a velocity of 3 ms^-1 in a direction 60^@ from the horizontal y - axis, on the smooth inclined plane (Fig. 5.197). The motion of sphere takes place in the x - y plane. Calculate the magnitude v of its velocity after 2 s . .

A horizontal conveyor belt moves with a constant velocity V.A small block is projected with a velocity of 6m//s on it in a direction opposite to the direction of motion of the belt The block comes to rest relative to the belt in a time 4s. mu =0.3, g =10 .m//s^(2) Find V .

A horizontal converyor belt moves with a constant velocity V. A small block is projected with a velocity of 6 mis on it in a direction opposite to the direction of motion of the belt. The block comes to rest relative to the belt in a time 4s. mu = 0.3 g, g= 10 m//s^(2) Find V

A horizontal converyor belt moves with a constant velocity V. A small block is projected with a velocity of 6 mis on it in a direction opposite to the direction of motion of the belt. The block comes to rest relative to the belt in a time 4s. mu = 0.3 g, g= 10 m//s^(2) Find V

A particle is projected upwards with a velocity of 100 m//s at an angle of 60^(@) with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m//s^(2) .