A soap film in formed on a frame of area `4xx10^(-3)m^(2)`. If the area of the film in reduced to half, then the change in the potential energy of the film is (surface tension of soap solution`=40xx10^(-3)N//m)`

What is the potential energy of soap film formed of area 2xx10^-3m^2 ? (surface tension of soap solution 40xx10^3N/m ).

There is a soap film on a rectangular frame of wire of area 4 xx 4 cm^(2) . If the area of the frame is increased to 4 xx 5 cm^(2) ,find the work done in the process. Given surface tension of soap films = 3 xx 10^(-2) Nm^(-1) .

A soap film in on a rectangular wire of size 4 cm xx 4 cm. If the size of the film is changed to 5 cm xx 5 cm, then calculate the work done in this process. The surface tension of soap film is 6xx10^(-2) Nm^(-1)

A soap film is on a rectangular wire ring of size 5cm ** 4 cm . If the size of the film is changed to 5cm xx 5cm , then calculate the work done in this process. The surface tension of soap film is 5 xx 10^(-2) Nm^(-1) .

A soap film is on a rectangular wire ring of size 2 cm times 3 cm. If the size of the film is changed to 3 cm times 3 cm, calculate the work done in this process. (The surface tension of soap solution is 3.0 times 10^(-2)Nm^(-1)) .