A solution of sucrose (molar mass `= 342 g mol^(-1))` has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the solution obtained will be: `(K_(f)` for water `= 1.86 K kg mol^(-1))`

A solution of sucrose (molar mass =342 g mol^(-1) ) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be ( K_(f) for water = 1.86K kg mol^(-1) )

A solution of sucrose (molar mass =342 g mol^(-1) ) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The depression in freezing point of the solution obtained will be ( K_(f) for water = 1.86K kg mol^(-1) )

A solution of sucrose (molar mass 342 "gmol"^(-1) ) has been produced by dissolving 68.5g sucrose in 1000g water. The freezing point of the solution obtained will be ( K_f for H_2O = 1.86 kg "mol"^(-1) )

A solution of sucrose (molar mass 342g mol^(-1) has been produced by dissolving 68.5g sucrose in 1000g water .The freezing point of the solution obtained will be (K_(f) for H_(2)O=1.86kgmol^(-1))

A solution of sucrose (molar mass =342) is prepared by dissolving 688.4 g in 1000 g of water. Calculate The freezing point of solution.

A solution of sucrose (molar mass =342) is prepared by dissolving 68.4 g in 1000 g of water. Calculate The freezing point of solution.