The entropy change for the fusion of `1 mol` of a solid which melts at `27^(@)C` is (latent heat of fusion `=600 kcal mol^(-1)`)

Calculate the change in entropy for the fusion of 1 mol of ice. The melting point of ice is 273 K and molar enthalpy of fusion of ice = 6KJmol^(-1)

Calculate the change in entropy for the fusion of 1 mol of ice. The melting point of ice is 300K and molar enthalpy of fustion for ice = 6.0 k J mol^(-1) .

Calculate the change in entropy for the fusion of 1 mol of ice. The melting point of ice is 300K and molar enthalpy of fustion for ice = 6.0 k J mol^(-1) .

What is the entrophy change in JK^(-1) during the melting og 27.3 g ice at 0^(@)C ?(Latent heat of fusion of ice =330 Jg^(-1)

Latent heat of fusion / melting of ice:

Latent heat of fusion / melting of ice:

Calculate the entropy change (DeltaS) when 1 mol of ice at 0^(@)C is converted into water at 0^(@)C . Heat of fusion of ice at 0^(@)C is 1436 cal per mol.