In LCR series circuit , an alternating emf e and current `i` are given by the equations `e = sin (100 t) ` volt .
`i=100 sin (100 t + (pi)/(3))` mA
The average power dissipated in the circuit will be

In LCR series circuit, an alternating e.m.f. 'e' and current 'I' are given by the equations e=100sin(100t) volt and I=100sin(100t+(pi)/(3))mA The average power dissipated in the circuit will be

In a series LCR circuit , and alternating emf (v) and current (i) are given by the equation v=v_(0) sin omegat, i=i_(0)sin (omegat+(pi)/(3)) . The average power dissipated in the circuit over a cycle of AC is

In an a.c circuit, V & I are given by V = 100 sin (100 t) volt. I = 100 sin (100 t + (pi)/(3)) mA The power dissipated in the circuit is:

In a series L.C.R. circuit alternating emf (v) and current (i) are given by the equation v=v_(0) sin omega t , i=i_(0)sin(omega t+(pi)/(3)) The average power dissipated in the circuit over a cycle of AC is

In an A.C. circuit, E=100 sin (500 t) volt and I=1000 sin(500 t +(pi)/3) mA . The power dissipated in the circuit is

In an a.c circuit, V & I are given by V = 100 sin (100 t) volt. I = 100 sin (100 t + (pi)/(2)) mA The power dissipated in the circuit is:

In a series LCR circuit, an alternating emf (V) and current (I) are given by the equation V =V_0sinomegat,I=I_0sin(omegat+pi/3) The average power dissipated in the circuit over a cycle of AC is

In a series LCR circuit, an alternating emf (V) and current (I) are given by the equation V =V_0sinomegat,I=I_0sin(omegat+pi/3) The average power dissipated in the circuit over a cycle of AC is