A hyperbola does not have mutually perpendicular tangents, then its eccentricity can be

If the ellipse x^(2)+2y^(2)=4 and the hyperbola S = 0 have same end points of the latus rectum, then the eccentricity of the hyperbola can be

If the ellipse x^(2)+2y^(2)=4 and the hyperbola S = 0 have same end points of the latus rectum, then the eccentricity of the hyperbola can be

If the ellipse x^(2)+2y^(2)=4 and the hyperbola S = 0 have same end points of the latus rectum, then the eccentricity of the hyperbola can be

If the ellipse x^(2)+2y^(2)=4 and the hyperbola S = 0 have same end points of the latus rectum, then the eccentricity of the hyperbola can be

If the latus rectum of a hyperbola is equal to half of its transverse axis, then its eccentricity is -

Tangents are drawn from the point (17, 7) to the circle x^2+y^2=169 , Statement I The tangents are mutually perpendicular Statement, ll The locus of the points frorn which mutually perpendicular tangents can be drawn to the given circle is x^2 +y^2=338

When the eccentricity 'e ' of a hyperbola S=0 lies between 1 and sqrt2 then the number of perpendicular tangents that can be drawn to the hyperbola is