The correct combination of three resistances `1Omega, 2Omega and 3Omega` to get equivalent resistance `(11)/(5)Omega` is

Given three resistors of resistances 1 Omega, 2Omega and 3Omega . How will you combine them to get an equivalent resistance of (11)/(5) Omega ?

In which combination three resistance 5Omega,10Omega & 15Omega are connected to give equivalent resistance will be less than 5Omega ? In domestic wearing gadgets are connected in which combination and why?

The total resistance in the parallel combination of three resistances 9Omega, 7Omega and 5Omega

The total resistance in the parallel combination of three resistances 9Omega, 7Omega and 5Omega

Given the resistance of 1Omega,2Omega,3Omega, how will you combine them to get an equivalent resistance of: (11//5)Omega