A uniform rod `AB` of mass `m` length `2a` is allowed to fall under gravity with `AB` in horizontal. When the speed of the rod is `v` suddenly the end `A` is fixed. Find the angular velocity with which it begins to rotate.

A uniform rod AB of mass m and length 2a is falling freely without rotation under gravity with AB horizontal. Suddenly the end A is fixed when the speed of the rod is v. The angular speed which the rod begains to rotate is

A uniform rod AB of length l rotating with an angular velocity omega while its centre moves with a linear velocity v=(omegal)/(6) If the end A of the rod is suddenly fixed, the angular velocity of

A uniform rod of mass m and length l is pivoted smoothly at point O as shown in figure. If a horizontal force F acts at the bottom of the rod and omega is the angular velocity of the rod which is a function of angle of rotation theta , then the maximum angular displacement of the rod is (Acceleration due to gravity, g)

A uniform rod of mass m=2 kg and length l is kept on a smooth horizontal plane. If the ends A and B of the rod move with speeds v and 2v respectively perpendicular to the rod, find the: a. angulr velocity of CM of the rod. b. Kinetic energy of the rod (in Joule).

A uniform rod of mass m=2 kg and length l is kept on a smooth horizontal plane. If the ends A and B of the rod move with speeds v and 2v respectively perpendicular to the rod, find the: a. angulr velocity of CM of the rod. b. Kinetic energy of the rod (in Joule).

A uniform rod of mass m and length l is pivoted smoothly at O . A horizontal force acts at the bottom of the rod. a. Find the angular velocity of the rod as the function of angle of rotation theta. b.What is the maximum angular displacement of the rod?

A uniform rod of mass m and length l is pivoted smoothly at O . A horizontal force acts at the bottom of the rod. a. Find the angular velocity of the rod as the function of angle of rotation theta. b.What is the maximum angular displacement of the rod?