The equation of the reflection of the hyperbola`(x-4)^2/16-(y-3)^2/9=1` about the line x+y-2 = 0 is

If the equation on reflection of ((x-4)^(2))/16+((y-3)^(2))/9=1 about the line x-y-2=0 is 16x^(2)+9y^(2)+k_(1)x-36y+k_(2)=0 then (k_(1)+k_(2))/22 is

The equation of the normal to the hyperbola x^2/16-y^2/9=1 at point (8,3sqrt3) is :

If the reflection of the ellipse ((x-4)^(2))/(16)+((y-3)^(2))/(9) =1 in the mirror line x -y -2 = 0 is k_(1)x^(2)+k_(2)y^(2)-160x -36y +292 = 0 , then (k_(1)+k_(2))/(5) is equal to

If the reflection of the ellipse ((x-4)^(2))/(16)+((y-3)^(2))/(9) =1 in the mirror line x -y -2 = 0 is k_(1)x^(2)+k_(2)y^(2)-160x -36y +292 = 0 , then (k_(1)+k_(2))/(5) is equal to

If the reflection of the ellipse ((x-4)^(2))/(16)+((y-3)^(2))/(9) =1 in the mirror line x -y -2 = 0 is k_(1)x^(2)+k_(2)y^(2)-160x -36y +292 = 0 , then (k_(1)+k_(2))/(5) is equal to

The equation to the normal to the hyperbola (x^(2))/(16)-(y^(2))/(9)=1 "at "(-4,0) is

The equation of the conjugate axis of the hyperbola ((x-5)^(2))/(16) -((y-4)^(2))/(9) =1 is

The equation of the axes of the hyperbola 9x^(2) -16y^(2) +72x -32y -16=0 are

Find the equation of normal to the hyperbola (x^(2))/(16)-(y^(2))/(9)=1 at (-4,0)