The melting point of a solid is `300K` and its latent heat of fusion is `600 cal mol^(-1)`. The entropy change for the fusion of 1 mole of the solid ( in cal `K^(-1))` at the same tempertre would be `:`

The melting point of a solid is 300K and its latent heat of fusion is 600 cal mol^(-1) . The entropy change for the fusion of 1 mole of the soli (in cal K^(-1) ) at the same temperature would be:

The thermodynamic property that measures the extent of molecular disorder is called entropy. The direction of a spontaneous process for which the energy is constant is always the one that increases the molecular disorder. Entropy change of phase transformation can be calculated using Trouton's formula (DeltaS= (DeltaH)/(T)) . In the reversible adiabatic process, however, DeltaS will be zero. The rise in temperature in isobaric and isochoric conditions is found to increase the randomness or entropy of the system. DeltaS= 2.303 C log (T_(1)//T_(2)), (C = C_(P) or C_(V)) The melting point of a solid is 300K and its latent heat of fusion is 600 cal mol^(-1) . The entropy change for the fusion of 1 mole of the soli (in cal K^(-1) ) at the same temperature would be:

The thermodynamic property that measures the extent of molecular disorder is called entropy. Entropy change of phase transformation can be calculated using Trouton's formula (DeltaS = DeltaH//T) . In the reversible adiabatic process, however, DeltaS will be zero. the rise in temperature in isobaric and isochoric conditions is found to increase the randomness or entropy of the system. DeltaS = 2.303 C log (T_(1)//T_(2)) The melting point of a solid is 200K and its latent heat of fusion is 400cal mol^(-1) . The entropy changes for the fusion of 1 mole of the solid (in cal K^(-1)) at the same temperature would be

The thermodynamic property that measures the extent of molecular disorder is called entropy. Entropy change of phase transformation can be calculated using Trouton's formula (DeltaS = DeltaH//T) . In the reversible adiabatic process, however, DeltaS will be zero. the rise in temperature in isobaric and isochoric conditions is found to increase the randomness or entropy of the system. DeltaS = 2.303 C log (T_(1)//T_(2)) The melting point of a solid is 200K and its latent heat of fusion is 400cal mol^(-1) . The entropy changes for the fusion of 1 mole of the solid (in cal K^(-1)) at the same temperature would be

Melting point of a solid is x K and its latent heat of fusion is 600 cal mol^(-1) . The entropy change for fusion of 1 mol solid is 2 cal mol^(-1)K^(-1) . The value of x will be:

Melting point of a solid is xK and its latent heat of fusion is 600 cal mol^(-1) . The entropy changes for fusion of 1 mol solid is 2 cal mol^(-1) K^(-1) . The value of x will be

Latent heat of fusion of ice is 6kJ mol^(-1) . Calculate the entropy change in the fusion of ice.