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Vapour pressure in mm Hg of 0.1 mole of ...

Vapour pressure in mm Hg of 0.1 mole of urea in 180 g of water at `25^(@)C` is (The vapour pressure of water at `25^(@) C` is 24 mm Hg)

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Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution ( in mm of Hg ) of 0.1 moles of urea in 180 grams of water at 25^(@)C in ( The vapour pressure of water at 25^(@)C is 24 mm Hg )

Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution ( in mm of Hg ) of 0.1 moles of urea in 180 grams of water at 25^(@)C in ( The vapour pressure of water at 25^(@)C is 24 mm Hg )

How many grams of glucose are required to prepare an aqueous solution of glucose having a vapour pressure of 23.324 mm Hg at 25^@ C in 100 g of water ? The vapour pressure of pure water at 25^@C is 23.8 mm Hg. (Molar mass of glucose =180 mol ^(-1) )

18.2 g of urea is dissolved in 100g of water at 50^(@)C . The lowering of vapour pressure produced is 5 mm Hg. Calculate the molecular mass of urea. The vapour pressure of water at 50^(@)C is 92 mm Hg.

Calculate the vapour pressure lowering caused by the addition of 68.4 g of sucrose (molecular mass = 342) to 500 g of water if the vapour pressure of pure water at 25^(@)C is 20.0 mm Hg .

Calculate the vapour pressure lowering caused by the addition of 68.4 g of sucrose (molecular mass = 342) to 500 g of water if the vapour pressure of pure water at 25^(@)C is 20.0 mm Hg .

Calculate the vapour pressure lowering caused by the addition of 68.4 g of sucrose (molecular mass = 342) to 500 g of water if the vapour pressure of pure water at 25^(@)C is 20.0 mm Hg .

Calculate the vapour pressure lowering caused by addition of 50g of sucrose (molecular mass = 342) to 500g of water if the vapour pressure of pure water at 25^(@)C is 23.8 mm Hg .