The equilibrium constant for the reaction,
`SO_3(g)hArr SO_2(g)+1/2O_2(g)` is `K_C=4.9xx10^(-2)` . The value of `K_C` for the reaction `2SO_2(g) + O_2 hArr 2SO_(3) (g)` will be :

The equilibrium constant for the reation, SO_3(g) hArr SO_2( g) +(1)/(2) O_2(g) is K_c= 4.9 xx 10^(-2) The value of K_c for the reaction 2SO_2(g) + O_2(g) hArr 2SO_3(g), will be

The equilibrium constant for the reaction SO_3(g) iff SO_2(g) +1/2 O_2(g) Is K_c = 4.9 xx10^-2 The value of K_c for the reaction 2SO_2(g) + O_2(g) iff 2SO_3(g) will be

The equilibrium constant for the given reaction: SO_(3(g))hArrSO_(2(g))+1//2O_(2(g)) , (K_(c)=4.9xx10^(-2)) The value of K_(c) for the reaction: 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) , will be :

The equilibrium constant for the given reaction: SO_(3(g))hArrSO_(2(g))+1//2O_(2(g)) , (K_(c)=4.9xx10^(-2)) The value of K_(c) for the reaction: 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) , will be :

The equilibrium constant for the reaction: SO_3(g) hArr SO_2(g) +1/2O_2(g) is 0.18 at 900 K. What will be the equilibrium constant for the reaction: 2SO_2(g) + O_2(g) hArr SO_3(g)

Based on the equilibrium constant for the reaction below : 2SO_3(g)hArr2SO_2(g)+O_2(g) " " K=1.8xx10^(-5) What is the equilibrium constant for the reaction SO_2(g)+1/2O_2(g)hArr SO_3(g) " " K=?

The equilibrium constant for the reaction N_2(g)+O_2(g) hArr 2NO(g) at temperature T is 4xx10^(-4) .The value of K_C for the reaction, NO(g) hArr 1/2 N_2(g)+1/2O_2(g) at the same temperature is :