A ball is thrown vertically downward with velocity of 20 m/s from top of tower. It hits ground after some time with a velocity of 80 m /s . Height of tower is

A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower,It hits the ground after some time with a velocity of 80m/s .The height of the tower is : (g=10m/g^(2))

A ball is thrown vertically upward with velocity 20 m//s from a tower of height 60 m. After how much time and with what velocity will it strike the ground?

[" A ball is thrown vertically downward "],[" with velocity u from the top of a tower."],[" It strikes the ground with a velocity "3u" ."],[" The time taken by the ball to reach the "],[" ground is given by "]

A ball is thrown vertically upward with a velocity u from the top of a tower. If it strikes the ground with velocity 3u, the time taken by the ball to reach the ground is

A ball is thrown vertically upward with a velocity u from the top of a tower. If it strikes the ground with velocity 3u, the time taken by the ball to reach the ground is

A ball is thrown vertically upwards with velocity of 25m/s from the top of a tower of height 30m . How long will if travel before it hits the ground ?

A ball is thrown vertically upwards from the top of a tower with a velocity of 10m/s. If the ball falls on the ground after 5 seconds, the height of the tower will be? (use g=10m/ s^(2) )

A ball is thrown vertically up from the top of a tower with velocity 10 m//s . It reaches the ground in 5s. Calculate the following - (a) Height of tower (b) Striking velocity of particle at ground (c ) Distance traversed by particle. (d) Average speed & average velocity of particle.

A stone is thrown upwards with initial velocity 'u' from top of a tower and it reaches to ground with velocity '3u' then height of the tower is ......