Home
Class 11
CHEMISTRY
The mean free path of the molecules of a...

The mean free path of the molecules of a certain gas at `300 K` is `2.6xx10^(-5)m`. The collision diameter of the molecule is `0.26m`. Calculate (`a`) the pressure of the gas and (`b`) the number per unit volume of the gas.

Promotional Banner

Similar Questions

Explore conceptually related problems

Mean free path of a gas molecule is

Mean free path of a gas molecule is :

The mean free path of the molecules of a gas in a chamber at 30^@ is 2.6 xx10^(-5) m assuming that the collision diameter is 0.26 xx10^(-9) m calculate the pressure of gas and the no per unit volume of gas

The mean free path of a gas molecule is the distance

The mean free path of a gas molecule is the distance

The mean free path of molecules of an ideal gas of diameter d id proportional to

The mean free path of molecules of an ideal gas of diameter d is proportional to