A particle of mass m=1kg is lying at rest on x-axis, experiences a net force given by law `F=x(3x-2)` Newton, where x is the x-coordinate of the particle in meters. The magnitude of minimum velocity in negative x-direction to be imparted to the particle placed at x=4 meters such that it reaches the origin is `sqrt(P/27) m//s`. find the value of P.

A particle of mass of mass m = 1 kg is lying on x-axis experiences a force given by F = x(3x-2) Newton, where x is the x-coordinate of the particle in meters. The points where the particle is in equilibrium are-

A particle of mass m=1 kg lying on x-axis experiences a force given by law F=x(3x-2) newton, where x is the x-coordinate of the particle in meters. The points on x-axis where the particle in meters. The points on x-axis where the particle is in equilibrium are (a) x=0 (b) x=1/3 (c) x=2/3 (d) x=1

A particle of mass m=1 kg lying on x-axis experiences a force given by law F=x(3x-2) newton, where x is the x-coordinate of the particle in meters. The points on x-axis where the particle in meters. The points on x-axis where the particle is in equilibrium are (a) x=0 (b) x=1/3 (c) x=2/3 (d) x=1

A particle of mass m=1kg lying on x-axis experiences a force given by law F=x(3x-2) Newton. Where x is the x-coordinate of the particle in meters. vec(x=0x=4 (a) Locate the point on x-axis where the particle is in equilibrium. (b) Draw the graph of variation of force F (y-axis) with x-coordinate of the particle (x-axis). Hence or otherwise indicate at which positions the particle is in stable or unstable equilibrium. (c ) What is the minimum speed to be imparted to the particle placed at x=4 meters such that it reaches tha origin.

A particle of mass m=1kg lying on x-axis experiences a force given by law F=x(3x-2) Newton. Where x is the x-coordinate of the particle in meters. vec(x=0x=4 (a) Locate the point on x-axis where the particle is in equilibrium. (b) Draw the graph of variation of force F (y-axis) with x-coordinate of the particle (x-axis). Hence or otherwise indicate at which positions the particle is in stable or unstable equilibrium. (c ) What is the minimum speed to be imparted to the particle placed at x=4 meters such that it reaches tha origin.

The velocity of a particle moving along x-axis is given as v=x^(2)-5x+4 (in m // s) where x denotes the x-coordinate of the particle in metres. Find the magnitude of acceleration of the particle when the velocity of particle is zero?

The velocity of a particle moving along x-axis is given as v=x^(2)-5x+4 (in m // s) where x denotes the x-coordinate of the particle in metres. Find the magnitude of acceleration of the particle when the velocity of particle is zero?

The velocity of a particle moving along x-axis is given as v=x^(2)-5x+4 (in m // s) where x denotes the x-coordinate of the particle in metres. Find the magnitude of acceleration of the particle when the velocity of particle is zero?

A particle is moving along the x-axis whose acceleration is given by a= 3x-4 , where x is the location of the particle. At t = 0, the particle is at rest at x = 4//3m . The distance travelled by the particles in 5 s is