Home
Class 12
CHEMISTRY
The enthalpy change for the following re...

The enthalpy change for the following reactions are:
`C_("diamond")+O_(2(g)) rarr CO_(2(g))" "DeltaH=-395.3 KJ "mol"^(-1)`
`C_("graphite")+O_(2(g)) rarr CO_(2(g)) " "DeltaH=-393.4 KJ "mol"^(-1)`
The enthalpy change for the transition
`C_("diamond")rarr C_("graphite")` will be :

Promotional Banner

Similar Questions

Explore conceptually related problems

1) C_("Graphite") + O_(2(g)) rarr CO_(2(g)) , DeltaH = -94 K.Cals 2) C_("Diamond") + O_(2(g)) rarr CO_(2(g)) , DeltaH =-94.5 K.Cals From the above data the heat of transition of C_("diamond") rarr C_("Graphite")

C_("diamond")+O_(2)(g)rarrCO_(2)(g),DeltaH=-395 kJ ...... (i) C_("graphite")+O_(2)(g)rarrCO_(2)(g),DeltaH=-393.5KJ" "…(ii) The DeltaH , when diamond is formed from graphite, is

For the following reaction, C_("diamond")+O_(2)toCO_(2)(g), DeltaH=-94.3" "kcal C_("graphite")+O_(2)toCO_(2)(g), DeltaH=-97.6" "kcal the heat require to change 1 g of C_("diamond")toC_("graphite") is:

Given (at 25^(@)C and 1 atm pressure): C(s, diamond) +O_(2)(g)toCO_(2)(g),DeltaH^(0)=-393.5kJ*mol^(-1) C(s, graphite) +O_(2)(g)toCO_(2)(g),DeltaH^(0)=-391.6kJ*mol^(-1) Find the standard heat of transition from graphite to diamond.

Given : C("diamond")+O_(2)rarrCO_(2),DeltaH=-395 kJ C("graphite")+O_(2)rarrCO_(2),DeltaH=-393 kJ The enthalpy of formation of diamond from graphite is

Given : C("diamond")+O_(2)rarrCO_(2),DeltaH=-395 kJ C("graphite")+O_(2)rarrCO_(2),DeltaH=-393 kJ The enthalpy of formation of diamond from graphite is