Find the equilibrium constant `K_(p)` in `log K_(p)` if the standard free energy change of a reaction `DeltaG^(@)=-115kJ` at 298K is

If equilibrium constant for a reaction is K, then standard free energy change is :

If equilibrium constant for a reaction is 'K', then standard free energy change is :

The equilibrium constant of a reaction is 1xx10^(20) at 300 K . The standard free energy change for this reaction is :

The equilibrium constant of a reaction is 0.008 at 298 K. The standard free energy change of the reaction at the same temperature is :

The equilibrium constant of a reaction is 0.008 at 298 K. The standard free energy change of the reaction at the same temperature is

The equilibrium constant of a reaction is 0.008 at 298 K . The standard free energy change of the reaction at the same temperture is

Standard free energy change of a reaction is +150 kJ mol^(-1) . Calculate K_(p) at 30^(@)C .

The equilibrium constant foa a reaction is 1 xx 10^(20) at 300 K.Find the standard free energy vhange for this reaction.