The maximum area of the triangle formed by the points `(0,0). (acostheta ,b sin theta) and (a cos theta,-b sin theta)` (in square units)

The maximum area of the triangle formed by the points (0,0)*(a cos theta,b sin theta) and (a cos theta,-b sin theta) (in square units)

A : The maximum area of the triangle formed by the points (0, 0), (a cos theta, b sin theta), (a cos theta, -b sin theta) is (1)/(2)|ab| . R : Maximum value of sin theta is 1.

The maximum value of the area of the triangle with vertices (a,0) ,(a cos theta, b sin theta ) , (a cos theta, -b sin theta) is

The area of the triangle with vertices (a, 0), (a cos theta, b sin theta), (a cos theta, -b sin theta) is

The area of the triangle with vertices (a, 0), (a cos theta, b sin theta), (a cos theta, -b sin theta) is

If a gt 0, b gt 0 then the maximum area of the parallelogram whose three vertices are O(0,0), A(a cos theta, b sin theta) and B(a cos theta, -b sin theta) is

The centroid of a triangle formed by the points (0,0), (costheta , sin theta) and (sin theta , -cos theta) lie on the line y = 2x , then theta is

The centroid of a triangle formed by the points (0,0), ( cos theta, sin theta ) and ( sin theta, -cos theta ) lies on the line y = 2x, then is

The centroid of a triangle formed by the points (0, 0), (cos theta, sin theta) and (sin theta, -cos theta) lies on the line y=2x . Then theta is :