The point of concurrence of the lines `(3k+1) x-(2k+3)y+(9-k)=0` is

Find the point of concurrence of the set of lines (2+5k)x-3(1+2k)y+(2-k)=0

Find the point of concurrence of the set of lines (k+1)x + (k +2)y + 5 = 0

Show that the following equations represent a set of concurrent lines and hence find the point of concurrence. i) (2+5k)x-3(1+2k)y+(2-k)=0, Ans: (5,4)]

Find the point of intersection of the lines 4x + 3y = 1 and 3x - y + 9 = 0 . If this point lies on the line (2k - 1) x - 2y = 4 , find the value of k. The above question can also be stated as : If the lines 4x + 3y = 1, 3x – y + 9 = 0 and (2k - 1) x - 2y = 4 are concurrent (pass through the same point), find the value of k.

Equation of straight line that passes through the concurrence point of lines (2+k)x+(1-k)y+3-k=0 k in R and also through (3,1) is ......

Locus of the image of the point ( 2 ,3) in the line ( 2x - 3y + 4 ) + k ( x - 2y + 3 ) = 0 , k in RR is a _

Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0, k in R is a

Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0 , k in R, is a