यदि `triangleABC` में `(a + b +c)(b + c -a) = 3bc` तो दिखलाएँ कि `A = 60^(@)`.

Prove that if (a + b+ c)(b + c - a) = 3bc then A = 60^@

If(a + b + c)(b + c-a) = 3bc in /_\ABC , prove that A = 60^@

In DeltaABC, if (a+b+c)(b+c-a)=3bc , then A=

If, in triangleABC, B=3C , then: (b-c)/(2c)=

In a triangleABC , if 1/(b+c)+1/(c+a)=3/(a+b+c) , then angleC =

यदि triangleABC में (If इन triangleABC), a = (1)/(sqrt(6)-sqrt(2)), b = (1)/(sqrt(6)+sqrt(2)), C = 60^(@) तो सिद्ध कीजिए कि (Prove that) c = (sqrt(4))/(2) .

In triangleABC , If (1)/(b+c)+(1)/(c+a)=(3)/(a+b+c) , then cosC=

In triangleABC , If (1)/(b+c)+(1)/(c+a)=(3)/(a+b+c) , then cosC=

If in triangleABC,(c+a)/b+(c+b)/a=c/r then

In triangle ABC , AD bisects angle A and intersects BC at D. If BC = a ,AC = b and AB = c, then BD = ? त्रिभुज ABC में, AD कोण A को समद्विभाजित करता है तथा BC को D पर काटता है | यदि BC = a, AC = b और AB = c है, तो BD = ?